Ice displacing water question, - really bad

[mujadeo]

ice displacing water question, --need help really bad

Homework Statement

A rectangular block of ice 6 m on each side and 1.1 m thick floats in seawater. The density of the seawater is 1025 kg/m3. The density of ice is 917 kg/m3.

How high does the top of the ice block float above the water level?

please help!

Homework Equations

The Attempt at a Solution

1.1 x 917/1025 m = 984 cm (the amount of water displaced).
So, the ice sticks out of the water 1100-984 = 116cm = 1.16m

this is wrong though. sum1 please help!

 

[hage567]

1 m = 100 cm.

You need to use the volume of the ice in your calculation, not just its thickness.

 

[mujadeo]

(1.1 x 6 x 6) x 917/1025 m = 35.428cm (the amount of water displaced).
So, the ice sticks out of the water 1100-35.428 = 1064.572cm = 1.064m

still wrong though
?

 

[hage567]

(1.1 x 6 x 6) x 917/1025 m = 35.428cm (the amount of water displaced).
So, the ice sticks out of the water 1100-35.428 = 1064.572cm = 1.064m

still wrong though
?

Why are you saying this is in cm? The original dimensions were given in meters (at least they were in your original post).

So, the ice sticks out of the water 1100-35.428 = 1064.572cm = 1.064m

Again, you can't just use the thickness of the ice. How can you subtract a volume from a length? That makes no sense. Draw a diagram, it might help. Once you find the submerged volume, you can find the volume of the ice remaining above the water (since you know the entire volume of the ice). Then you can find the height.

1.1 m DOES NOT equal 1100 cm. Don't bother changing things to cm. Why don't you want to just leave it in meters?