Ideal Gas and finding final pressure

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SUMMARY

The discussion focuses on solving a gas law problem involving an automobile tire inflated to 28% of its original volume at an increased temperature from 10°C to 40°C. The key equation used is the Combined Gas Law, represented as (P_2)(V_2) / (P_1)(V_1) = T_2 / T_1. The final pressure, P_2, is calculated to be 3.95 atm by manipulating the equation and recognizing that the number of moles (n) remains constant throughout the process. The participants confirm that R, the ideal gas constant, is invariant in this scenario.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Familiarity with the Combined Gas Law
  • Basic algebraic manipulation skills
  • Knowledge of temperature conversion between Celsius and Kelvin
NEXT STEPS
  • Study the derivation and applications of the Combined Gas Law
  • Learn about the implications of constant moles in gas law problems
  • Explore temperature conversion methods and their significance in gas calculations
  • Investigate real-world applications of gas laws in automotive engineering
USEFUL FOR

Students studying chemistry, physics, or engineering, particularly those focusing on thermodynamics and gas laws, will benefit from this discussion.

puniverse
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Homework Statement



I'm trying to understand algebraically how the solution was arrived at for the following problem.

Automobile tire at normal atmosphere at 10 deg C.
Inflating the tire to 28% of original volume with an increase in temp to 40 deg C
What is the pressure?

Homework Equations



PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is a constant, and T is the temp

The Attempt at a Solution



The the solution is given in what appears as a ratio between the initial values and final values, and I'm just not understanding algebraically how the equation in step 1. was derived. Why would I divide the final values with the initial values?

1. (P_2)(V_2) / (P_1)(V_1) = nRT_2 / nRT_1

2. (P_2)(.28V_1) / (1 atm)(V_1) = T_2 / T_1

3. (.28)P_2) / (1 atm) = 313.15 K / 283.15 K

4. P_2 = 1.106 / .28

5. P_2 = 3.95 atm


Thanks for whatever enlightenment you might be able to give.
 
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Looks to me as if you need to use the Combined gas equation.
 
Welcome to PF puniverse!

In this case, you can take it as this R = PV/nT, and since R is a constant regardless or what happens, they equate both sides together and shifted the variables around.
 
Oh, I understand that. So it's like:

1. nR_1 = (P_1)(V_1) / T_1

2. nR_2 = (P_2)(V_2) / T_2

3. nR_1 = nR_2

4. (P_1)(V_1) / T_1 = (P_2)(V_2) / T_2 ... and then solve for P_2

Yup, that works. Thanks!

Quick question tho, would I be misunderstanding if I considered n a constant also? I mean, n as in the number of moles doesn't change in this situation does it?
 
In this situation, n is constant, since they are not pumping more air, but instead, increasing the temperature of the air inside. So yeah. nR is in fact constant, for this question.
 

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