Ideal Gas Law- finding gas density

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chantalprince
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Homework Statement



What is the density of radon gas at 0 degrees C and 1 atmosphere?


Homework Equations



PV= nRT
0 C = 273 K

density = mass/volume g/m^3

The Attempt at a Solution



I want density = g/m^3

Below are the units of PV = nRT. I thought that breaking it down would help me to see where the g's and the m^3 are- but so far its just confused me.

physicspressurething.jpg



I have been trying to manipulate PV = nRT so that the units eventually give me g/m^3. I think I got something close, but then realized that all I have to plug in is T and P. This is what I tried: P/R = nT/V Units end up: g/m^3 = 1/m^3 I'm not sure if that works out...


Nothing is changing so I can't cancel anything and then set up a proportion equation- What the heck do I do??
 
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chantalprince said:

Homework Statement



What is the density of radon gas at 0 degrees C and 1 atmosphere?


Homework Equations



PV= nRT
0 C = 273 K

density = mass/volume g/m^3

...

Nothing is changing so I can't cancel anything and then set up a proportion equation- What the heck do I do??
You won't find the answer with just PV=nRT. This is because mass of the gas molecules has no effect on P, V or T for an ideal gas.

Since density is mass/volume you need to relate mass to volume. What is the number of molecules per unit volume? What is the mass of a molecule of Radon gas?

AM
 
Thanks so much! I worked it out then referenced to the actual density of radon that I found online and it agrees :wink:

Thanks again AM.