Hg is spilled in a laboratory which measures 15.2m long, 6.6m wide, and 2.4m high. Find mercury vapor in grams at 20C room. Given vapor pressure of Hg = 1.7E-6 atm.
The Attempt at a Solution
Volume= 15.2*6.6*2.4 =240.768 m^3 = 240768 L
Temp = 20 + 273.15 = 293.15 K
P = 1.7E-6 atm
n= (1.7E-6)(240768 L)/ (0.08206 L atm/mol K)(293.15K)
n= 0.017 mol
= 3.4 g Hg
I'm not quite sure if this is how you calculate the mass of Hg. the next part of question asks if concentration of Hg exceed air quality reg. (0.050 mg Hg/m^3). According to my answer, it does exceed b/c 3.4g=3413mg/240.768m^3 = 14.2 mg Hg/m^3.
can someone check my work plz, thanks in advance. I have a feeling that the mass of Hg is a bit too high......