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## Homework Statement

Hg is spilled in a laboratory which measures 15.2m long, 6.6m wide, and 2.4m high. Find mercury vapor in grams at 20C room. Given vapor pressure of Hg = 1.7E-6 atm.

## Homework Equations

## The Attempt at a Solution

Volume= 15.2*6.6*2.4 =240.768 m^3 = 240768 L

Temp = 20 + 273.15 = 293.15 K

P = 1.7E-6 atm

PV =nRT

n= PV/RT

n= (1.7E-6)(240768 L)/ (0.08206 L atm/mol K)(293.15K)

n= 0.017 mol

0.017 mol*200.6g/mol

= 3.4 g Hg

I'm not quite sure if this is how you calculate the mass of Hg. the next part of question asks if concentration of Hg exceed air quality reg. (0.050 mg Hg/m^3). According to my answer, it does exceed b/c 3.4g=3413mg/240.768m^3 = 14.2 mg Hg/m^3.

can someone check my work plz, thanks in advance. I have a feeling that the mass of Hg is a bit too high......