Identity for the cross of a curl?

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SUMMARY

The discussion focuses on proving the vector identity for the expression (\nabla \times \vec{A}) \times \vec{A} using Levi-Civita symbols and the identity \(\epsilon_{kij}\epsilon_{kmn} = \delta_{im}\delta_{jn} - \delta_{in}\delta_{jm}\). The user derives the expression \([( \nabla \times \vec{A}) \times \vec{A}]_k = (\partial_j A_k)A_j - (\partial_k A_j)A_j\), but struggles to simplify it into a more recognizable form involving vectors and vector operators. The discussion highlights the challenges in vector calculus identities and the need for further exploration of simplification techniques.

PREREQUISITES
  • Understanding of vector calculus, specifically curl and cross product operations.
  • Familiarity with Levi-Civita symbols and their properties.
  • Knowledge of vector field operations and identities.
  • Basic understanding of tensor notation and Kronecker delta.
NEXT STEPS
  • Study vector calculus identities in detail, focusing on simplification techniques.
  • Learn about the applications of Levi-Civita symbols in physics and engineering.
  • Explore advanced topics in vector field theory, including divergence and gradient operations.
  • Investigate the relationship between vector identities and physical phenomena in electromagnetism.
USEFUL FOR

Mathematicians, physicists, and engineering students who are working with vector calculus and seeking to deepen their understanding of vector identities and their applications.

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Hello! I'm want to prove a vector identity for

(\nabla \times \vec{A}) \times \vec A

using the familiar method of levi-civita symbols and the identity

\epsilon_{kij}\epsilon{kmn} = \delta_{im}\delta_{jn} - \delta_{in}\delta{jm},
but I don't seem to come up with any usefull answer. I end up with that


[(\nabla \times \vec{A}) \times \vec A]_k = (\partial_j A_k)A_j - (\partial_k A_j)A_j
, which doesn't seem to reduce something familiar in terms of vectors and vector operators. Any idea how I might get there?
 
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