If a and b are rational numbers satisfying

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To prove Proposition 1.15, it is established that if a and b are real numbers with a < b, then there exist rational and irrational numbers between them. The Archimedean property is suggested as a key tool for the proof. The midpoint (a+b)/2 is shown to lie between a and b, providing a starting point for identifying numbers in that interval. The discussion emphasizes the need to demonstrate that this midpoint can represent both rational and irrational numbers. Utilizing specific examples, such as setting a = 0, is recommended to facilitate the proof.
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Homework Statement



Prove Proposition 1.15.

Proposition 1.15. If a and b are real numbers satisfying a<b, then there are rational numbers and irrational numbers between a and b.

Homework Equations



Professor said to use the Archimedean property

The Attempt at a Solution



a < b ---> (a+a)/2 < (a+b)/2 ---> a < (a+b)/2

Similarly,

a < b ---> (a+b)/2 < (b+b)/2 ---> (a+b)/2 < b

Hence a < (a+b)/2 < b

Now I need some way to show that (a+b)/2 can equal rational and irrational numbers. Any suggestions?
 
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Hi Jamin2112! :smile:

But you haven't used the Archimedean property.

Hint: try it with a = 0. :wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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