If a cylindrical tank of radius 1m rests on a platform 5m above the

In summary, the initial force applied by the water coming out from the orifice on the tank would be 10N, as calculated by multiplying the gravitational acceleration (g) by the density of water (103kg/m3) and the height of the tank (5m), and then multiplying by the area of the opening (10-4m2). This is slightly different from the expected answer of 5N, which could be due to variations in pressure caused by the small diameter of the opening.
  • #1
jeedoubts
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If a cylindrical tank of radius 1m rests on a platform 5m above the ground. Initially the tank is filled with water up to a height 5m. A plug whose area is 10-4m2 removed from an orifice on the side of the tank at the bottom.(density of water = 103kg/m3, g= 10m/s2).
i wanted to ask what would be the initial force applied by water coming out from orifice on tank?
 
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  • #2


jeedoubts said:
If a cylindrical tank of radius 1m rests on a platform 5m above the ground. Initially the tank is filled with water up to a height 5m. A plug whose area is 10-4m2 removed from an orifice on the side of the tank at the bottom.(density of water = 103kg/m3, g= 10m/s2).
i wanted to ask what would be the initial force applied by water coming out from orifice on tank?
The force is pressure times area- the water pressure times the area of the opening. The pressure is weight of water above the bottom divided by the area of the bottom- and since the weight of the water is just g times the density times the volume, which is itself base area times height, the pressure is just g times the density of water times the height of the tank. So the force at the opening is g times the density of water times the height of the tank times the area of the opening. Strictly speaking, since pressure changes with height and the opening is vertical, you should integrate over the area of the opening, but with it only few mm in diameter, just multiplying by the area is good enough.
 
  • #3


So the answer must be 5N but the answer is 10N can you explain this?
 

1. What is the volume of the cylindrical tank?

The volume of the cylindrical tank can be calculated using the formula V = πr²h, where r is the radius of the tank and h is the height of the tank.

2. How much liquid can the tank hold?

The amount of liquid the tank can hold depends on the volume of the tank and the level of liquid within the tank. To calculate the amount of liquid, you will need to know the height of the liquid in the tank.

3. What is the weight of the tank when it is filled with liquid?

The weight of the tank when it is filled with liquid will depend on the density of the liquid. You can calculate the weight by multiplying the density of the liquid by the volume of the liquid in the tank.

4. How much pressure does the tank exert on the platform?

The pressure exerted by the tank on the platform will depend on the weight of the tank and the liquid inside it. You can calculate the pressure using the formula P = F/A, where P is pressure, F is force, and A is the area of contact between the tank and the platform.

5. How high can the liquid be filled in the tank before the platform breaks?

The maximum height of the liquid that can be filled in the tank before the platform breaks will depend on the strength of the platform and the weight of the tank and liquid. You will need to calculate the weight of the tank and liquid and compare it to the maximum weight the platform can support before breaking.

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