- #1

icantadd

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## Homework Statement

Suppose b | a!(n-a)! and prove that b | n!

## Homework Equations

m | n <=> n = am

## The Attempt at a Solution

b | a!(n-a)! ,so that

a!(n-a)! = bs, so that

a!(n-a)!(nCa) = bs(nCa) (nCa is a combinations of n items)

n! = bs(nCa)

And so b is obviously a divisor of n!