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## Homework Statement

How long would a day have to be on Earth if there was zero net acceleration at the equator?

## Homework Equations

Ac=v^2/r

Vrotational=Ac / Radius of earth

g = 9.8m/ss

T = earth's circumference / rotational velocity

V= SQRT(Ac*R)

Earth's Radius = 6.37x10^6

Earth's circumference = 40023890.41

## The Attempt at a Solution

The real acceleration of earth due to it's rotation is .03m/ss, but it doesn't really matter to us because g=9.8m/ss so we can stay on Earth. so the net acceleration in 9.8 - .34

if there was a zero net acceleration, then the acceleration of earth due to it's rotation would have to be 9.8m/ss, right?

so doing V= SQRT(Ac*R), i get 7901.013m/s for the rotational velocity of the Earth.

T = earth's circumference / rotational velocity, i get 506.56s, or, .141hrs. Is that correct?