Ill you help me?"Unraveling the Mystery of 'e': Solving an Integral

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Homework Help Overview

The discussion revolves around understanding the mathematical constant 'e' in the context of integrals, particularly in quantum physics applications. The original poster expresses confusion about how to handle integrals involving 'e', especially when calculating limits from negative to positive infinity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of integrals involving 'e' and question the original poster's phrasing and mathematical notation. There are attempts to clarify the integral setup and the implications of using 'e' in calculations. Some participants suggest rephrasing the question mathematically and emphasize the importance of boundaries in integrals.

Discussion Status

The conversation is ongoing, with various participants attempting to clarify the original poster's questions and providing insights into the integral calculations. Some guidance has been offered regarding the use of polar coordinates and the limits of integration, but there is still a lack of consensus on the specific issues being faced.

Contextual Notes

Participants note that the original poster may be struggling with the transition to polar coordinates and the interpretation of boundaries in integrals. There is also mention of the need for clearer mathematical expressions to facilitate understanding.

  • #31
ah, you've calculated 4 times ∫00 dxdy …

that's 4 times ∫00π/2 drdθ, isn't it? :wink:
 
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  • #32
I think, I will not change the function when I calculate..
 

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  • #33
sorry, you're misunderstanding …

the "4" is ok :smile:

it's the "2π" in your limit which was wrong, and needed to be changed to "π/2" (in red in my last post) :wink:
 
  • #34
so, why did the function go from 0 to pi/2 ? :(

I don't understand that, on the other hand, the function could go from 0 to 2pi...

when can we see this kind of problems because I haven't figured out :(
 
  • #35
because your ∫∫ from 0 to ∞ was only over the first quadrant (x≥0, y≥0) …

that's 0 ≤ θ < π/2 :wink:

(if you'd kept to ∫∫ from -∞ to ∞, ie over all four quadrants, that would be 0 ≤ θ < 2π)
 
  • #36
thank you for everything :) this explain was clear.. by the way, which profession do you have? just curious for me:) are u student or working university? :)
 
  • #37
i am a little goldfish,

and my job is swimming around all day, and keeping an eye on things :smile:
 
  • #38
hahahaha:D, I think you don't want to talk about this.. okey , keep swimming:)
 

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