I'm hoping someone could check my answers.

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The discussion focuses on a physics problem involving a duck's movement, requiring calculations for total distance, average speed, total displacement, and average velocity. The total distance traveled by the duck is correctly calculated as 87 meters, leading to an average speed of 0.725 m/s. However, there is a mistake in the displacement calculation, where the correct eastward component should be 76.7 m instead of 65 m, resulting in a total displacement of 78 m. The average velocity is also misrepresented; the direction should reflect nearly south, not as initially stated. The corrections clarify the calculations and ensure accurate results in the problem-solving process.
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In 2.0 min., a duck travels 22m [36deg N of E] then paddles 65m [E 25deg S] determine
i) total distance, ii) average speed, iii)tatol displacement iv) average velocity.

Relevant equations: v%=d/t (for velocity and speed)

i) total distance 22m+65m=87m
ii) v%=87m/120s
v = 0.725m/s
iii) let N&E be positive NS comp. 22sin36deg=12.93, 65sin25deg= -27.47, 12.93-27.47= -14.54or 14.54
EW comp. 22cos36deg=17.79, 65cos25deg=58.91, 17.79+58.91= 76.7[E]

d^2=14.54m^2+58.91m^2
d=78m
iv) v=78m/120s
v=0.65m/s [E 79.3deg S]

Thanks for any help
Cheers!
 
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in iii) you write d^2=14.54m^2+58.91m^2 which should be d^2=14.54m^2+76.7m^2, but you have the correct final answer.

in iv) the direction is wrong. [E 79.3deg S] meant "79.3 degrees south of east" in the rest of the problem, so this is directed nearly south. the velocity was 76.7 meters to east and 14.54 meters south in 120 seconds.
 
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