Impact loading on a mass / mass-less beam

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SUMMARY

The discussion centers on the impact of a beam's mass on its deflection when a weight is dropped onto it. The initial analysis suggests that the mass of the beam does not influence the deflection, as the potential energy of the dropped mass converts entirely into strain energy. However, a counterpoint is raised regarding the conservation of energy, proposing that the beam's mass should also contribute potential energy, which could alter the deflection calculation. The key equations referenced include the strain energy formula and the relationship between potential and kinetic energy during deflection.

PREREQUISITES
  • Understanding of beam deflection principles
  • Familiarity with potential and kinetic energy concepts
  • Knowledge of conservation of energy in mechanical systems
  • Basic mechanics of materials, specifically strain energy calculations
NEXT STEPS
  • Study the effects of mass on beam deflection using finite element analysis (FEA)
  • Explore advanced beam theory, including Euler-Bernoulli beam theory
  • Investigate energy methods in structural analysis
  • Learn about dynamic loading effects on beams and their deflection
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Mechanical engineers, structural analysts, and students studying mechanics of materials who are interested in understanding the dynamics of beam deflection under load.

tjbr
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Hey guys, I've got a problem that I have been puzzling over for a long time now. I think that the mass of a beam should not affect the amount that the beam deflects when another mass is dropped on it, however my mechanics lecturer thinks otherwise, i don't understand his logic.

If I have a beam, which has no mass, and a weight is dropped onto the centre of the beam, then the deflection is easy to work out, we let the strain energy of the beam equal the potential energy of the mass:

1/2 P*delta = mg(h + delta)

and delta = PL^3/(48 EI)

However, if we say that the beam did have a mass, how would this effect the deflection? I was reasoning that the potential energy would be turned into kinetic energy when it hits the mass, however, when the beam is at its greatest deflection, the kinetic energy = 0. This means that some of the potential energy of the mass being dropped gets turned into kinetic energy, but ultimately it all gets turned into strain energy.

So does this mean that the weight of a beam plays no part in the deflection caused by dropping a mass onto it? It seems backwards to think so, but i don't see how it can't be the case, all the energy must end up as strain eventually!
 
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tjbr: If you, for simplicity, neglect energy losses, and if the beam mass is modeled as a lumped mass M, shouldn't the conservation of energy equation also include a term for the initial potential energy of the beam, M*g*delta? How would this affect your solution for delta?
 

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