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## Homework Statement

If dy/dx=xy^2 and x=1 when y=1, then y=

(A) x^2

(B) -2/(x^2 -3)

(C) x^2 + 3

(D) 2/(x^2 +1)

(E) (x^2 -3)/2

## Homework Equations

## The Attempt at a Solution

dy/dx=xy^2

dy=xy^2dx

dy/y^2=x dx

∫dy/y^2=∫x dx

-1/y = x^2/2 + C

y=-2/x^2 + C

1=-2/1^2 + C

C=3

y=-2/x^2 +3

but that's not the answer...

please help i have the AP test tomorrow.

thanks

much appreciated