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Homework Help: Implicit differentiation - messed up somewhere

  1. Dec 2, 2008 #1
    1. The problem statement, all variables and given/known data
    find d^2y/dx^2 at (1,1) for:
    x^2y + x^2 -y^2 = 1




    2. Relevant equations
    none



    3. The attempt at a solution
    i worked it all out but the answer im getting is not an option. could someone show me where i made a mistake? im not asking you to do the problem for me, just fix my error. this is what i did:
    first i found dy/dx:

    x^2(dy/dx) + y(2x) +2x -2y(dy/dx)=0
    (x^2 - 2y)(dy/dx) = -2xy - 2x
    dy/dx = (-2xy-2x)/(x^2-2y)
    when i put (1,1) in, i got 4

    then to find the second derivative i used the quotient rule:
    d^2y/dy^2 = [(x^2-2y) (-2x)(dy/dx) +y(-2) -2] - ((-2xy-2x)(2x-2)(dy/dx)]/(x^2-2y)^2

    then i just put the values in. for the x's and y's i put in 1, and for dy/dx i put in 4. i ended up with:
    [(-1 x -2 x 4 + -2 -2) - (-2 -2) x (2-2(4) ] / 1 = 28 ? but this answer is incorrect. what did i do wrong?


    Thanks so much!
     
  2. jcsd
  3. Dec 2, 2008 #2

    HallsofIvy

    User Avatar
    Science Advisor

    It's not necessary to solve for dy/dx- just use implicit differentiation again.

    You are correct that x^2(dy/dx) + y(2x) +2x -2y(dy/dx)= 0.

    Now, (x^2(dy/dx)'= x^2 d^2y/dx^2+ 2x dy/dx, (2xy)'= 2xy'+ 2y, and (2y dy/dx)'= 2y d^2y/dx^2+ 2 (dy/dx)^2. Put those together.
     
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