D_Tr
- 43
- 4
Homework Statement
(The fourth equation is the central one)
first, we have [itex]\frac{1}{r}=\frac{a}{b^2}(1+ecosθ)[/itex] and [itex]b^2=a^2(1-e^2)[/itex]
now using these two, we transform
[itex]acosψ=ae+rcosθ[/itex] into [itex](1-ecosψ)(1+ecosθ)=\frac{b^2}{a^2}[/itex]
we want to find [itex]dθ/dψ[/itex], and the author performs an inplicit differentiation, and the result in the book is (treating θ as a function of ψ)
[tex]dθ/dψ=\frac{b}{a(1-ecosψ)}[/tex]
Homework Equations
stated above
The Attempt at a Solution
I performed the implicit differentiation and got:
[tex]esinψ(1+ecosθ)-esinθ\frac{dθ}{dψ}(1-ecosψ)=0[/tex]
Is my implicit differentiation wrong or are some transformations needed? I tried to match the result in the book using the first two equations together with my result without success..