Improper Integrals and the Comparison Theorem

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SUMMARY

The forum discussion centers on the application of the Comparison Theorem to evaluate the convergence of the improper integral f(x) = ∫ from 42 to ∞ of (42 + 42^-x)/x dx. The user compared this integral to g(x) = ∫ from 42 to ∞ of 1/x dx, which was determined to be divergent. The conclusion reached is that f(x) is also divergent, as confirmed by community members.

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Lanza52
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Use the Comparisom Theorem to determine if

[tex]f(x) = \int^{\infty}_{42} \frac{42+42^-x}{x}dx[/tex]

is convergent or divergent.

I compared it to [tex]g(x)=\int^{\infty}_{42} \frac{1}{x}dx[/tex]

[tex]\int^{\infty}_{42} \frac{1}{x}dx = Lim_{t->\infty}\int^{t}_{42} \frac{1}{x}dx[/tex]

Take the antiderivative, and the limit as t approaches infinity of ln(t)-ln(42) is infinity.

So divergent.

Looking for check. Thanks =P
 
Last edited:
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Yes that is correct.
 

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