# Homework Help: Impulsive delta v hyperbolic and elliptical orbit

1. Oct 11, 2009

### orbitsnerd

1. The problem statement, all variables and given/known data
On July 1, 2004, the Cassini spacecraft approached
Saturn with hyperbolic excess velocity 5.5 km/s to
swing by the planet at the closest approach distance
rp = 80,680 km. Compute the impulsive ΔV
required for a maneuver performed at the closest
approach to Saturn to transfer the Cassini spacecraft
into a 116-day elliptical orbit having the same
periapsis point as the approach (hyperbolic)
trajectory.
rp=80,680 km
vinf=5.5 km/s
T=116 days
GMsaturn=3.7931187e7 km^3/s^2

2. Relevant equations
vinf=sqrt(GMsaturn/a)

3. The attempt at a solution
I know it is an in-plane maneuver going from a hyperbolic approach to an ecliptic approach. If the vinf=sqrt(GM/a) is correct, I get a=1,253,923 km.
I am pretty much lost on how to complete this problem. I have done previous examples of Hohmann transfers and heliocentric orbits including the various velocities involved. Any help would be appreciated.
Thanks!

2. Oct 12, 2009

### gabbagabbahey

Hi orbitsnerd, welcome to PF!

What does vinf physically represent? Does that really correspond to the value of 5.5km/s excess velocity you are given?

What must be true of the total energy (kinetic plus gravitational potential) of Cassini for it to be captured by Saturn's gravity? If Cassini is traveling at 5.5km/s in excess velocity, doesn't that mean it is traveling 5.5km/s too fast to be captured? What does that tell you it's total energy is? What would its total energy be if it were traveling in a 116 Day elliptical orbit having the same
periapsis point as the approach (hyperbolic)? What is the difference in these two energies? What chance in speed would account for this difference?

3. Oct 12, 2009

### orbitsnerd

I was able to begin the problem (so I hope) this way:
T=2Pi sqrt(a^3/mu) where a=299290 km
e=1-(rp/a) so e=.7304
a=ra+rp/2 where ra=517900 km
vp=sqrt((2mu/rp)-(2mu/rp+ra))=28.53 km/s
I am using mu=musaturn=3,7931187e7 km^3/s^2.

Is this this correct initial approach? I am still a bit lost by what you meant by 5.5 km/s not being vinf.

For the energy equation are you referring to the E=(v^2/2)-(mu/r)?
Thanks.

4. Oct 14, 2009