An airplane, whose air speed is 600km/h is supposed to flyy in a straight path 35 degrees north of east. But a steady 100 km/h wind is blowing from the north. In what direction should the plane head?
Here is an answer by someone(is it right?)
Vp (vector velocity of the plane) = 600cos35i + 600sin35j
Vw (vector velocity of the wind) = -100j
The direction in which it shud go is the direction of the velocity of the plane relative to the wind, Vpw
As a rule Vpw= Vp - Vw
=> Vpw= 491.5i + 344.1j + 100j
= 491.5i + 444.1j
|Vpw|= 662.4 km/h (speed at which the plane heads, direction is given by tanA=j/i=444.1/491.5)
tanA = 444.1/491.5
A = 42 degrees.
The plane shud head East42North.