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Question:

An airplane, whose air speed is 600km/h is supposed to flyy in a straight path 35 degrees north of east. But a steady 100 km/h wind is blowing from the north. In what direction should the plane head?

Here is an answer by someone(is it right?)

Vp (vector velocity of the plane) = 600cos35i + 600sin35j

Vw (vector velocity of the wind) = -100j

The direction in which it shud go is the direction of the velocity of the plane relative to the wind, Vpw

As a rule Vpw= Vp - Vw

=> Vpw= 491.5i + 344.1j + 100j

= 491.5i + 444.1j

|Vpw|= 662.4 km/h (speed at which the plane heads, direction is given by tanA=j/i=444.1/491.5)

tanA = 444.1/491.5

A = 42 degrees.

The plane shud head East42North.

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# Homework Help: In what direction should the plane head?

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