Incident electric field attenuation near a metallic plate

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SUMMARY

The discussion focuses on the phenomenon of electric field attenuation near a metallic plate, specifically in the context of antenna radiation patterns visualized using CST (Computer Simulation Technology) software. It is established that the electric field (E-field) at the surface of a conductor is zero, leading to complete reflection of the incident E-field with a phase that opposes the incoming field. The interaction occurs as electrons on the metal surface respond to the incident E-field, creating a reactive force that contributes to the observed attenuation. Additionally, the size of the metallic plate relative to the wavelength significantly influences its effect on the incident field.

PREREQUISITES
  • Understanding of electromagnetic field theory
  • Familiarity with CST (Computer Simulation Technology) software
  • Knowledge of conductor behavior in electromagnetic fields
  • Basic principles of wave propagation and reflection
NEXT STEPS
  • Study the principles of electromagnetic wave reflection and transmission at boundaries
  • Learn about the behavior of electric fields in conductors and dielectrics
  • Explore dynamic versus electrostatic cases in electromagnetic theory
  • Investigate the effects of plate size on electromagnetic interactions
USEFUL FOR

Electromagnetic engineers, antenna designers, and students of electrical engineering seeking to deepen their understanding of electric field behavior near conductive materials.

Bobymayor
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Hello everybody,

I was visualizing the electric field radiation pattern of an antenna in a 3D EM simulation software (CST), and to see it with my eyes made me realize something I probably heard during my studies but forgot. What is the phenomenon behind what you can see below, which is the E-field attenuation when it is near a metallic plate (in the middle, side view), while the E-field is propagating from right to left ?

Efield_plate.png


I believe it is related to charges inside the metal that radiates an E-field all around the surface, opposite to incident E-field ?

Thanks !
 
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That is correct. The metal is a conductor, so there can be no E-field at its surface. This means that all the energy is reflected and the phase of the reflected E-field is opposing the incident field. Another way to look at is that the electrons at the surface of the metal move in response to the incident E-field and, as per Newton, exert a force of reaction against it. The incident E-field does work against this force. The force is created by the static E-field lines of the electrons being bent due to the acceleration, and the direction of the radiated, tangential component is opposite to the incident field.
Notice that if the plate is smaller than half a wavelength, its effect on the incident field is very small.
 
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Thank you for your answer ! I will continue to dig into this, I only found courses introducing this behavior but for electrostatic case, which I guess is necessary to understand the dynamic case.
 

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