Inclined plane moment of inertia

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SUMMARY

The discussion focuses on calculating the acceleration of a block sliding down an inclined plane and the tension in a string connected to a flywheel. The block has a mass of 5.00 kg, a 36.9° incline, and a kinetic friction coefficient of 0.25. The flywheel has a mass of 25.0 kg and a moment of inertia of 0.500 kg·m². The final calculated values are an acceleration of 1.123 m/s² and a tension of 14 N in the string.

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  • Understanding of Newton's second law of motion
  • Knowledge of torque and rotational dynamics
  • Familiarity with the concept of moment of inertia
  • Basic trigonometry for resolving forces on inclined planes
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Homework Statement



A block with mass m = 5.00 kg slides down a surface inclined 36.9 to the horizontal. The coefficient of kinetic friction is 0.25. A string attached to the block is wrapped around a flywheel has mass 25.0 kg and moment of inertia 0.500 kgm2 with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.200 m from that axis.
a) What is the acceleration of the block down the plane
b) What is the tension in the string

Homework Equations





The Attempt at a Solution


Ok I've been having a lot of trouble with things involving moments of inertia. I've found the friction that opposes the motion to be 9.81N. but how do i calculate the opposing force that the flywheel provides? any help is appreciated, as always..
 
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Could you please show a picture?

ehild
 
Could you please show a picture?

ehild
 
How do you show a picture in a reply?? I've attached it as a word doc.
 

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Use the relationship \alpha=a/r and solve the torque equation for a.
 
you mean mg-T=ma??
 
First sum up all of the forces for the block.

\SigmaFx=sin\theta*Fg-Ff-T=ma

Then get the pulley

\Sigma\tau=I*\alpha
 
Ok ill do that and report back with my answer, thanks.
 
Hey is the answer a=1.123m/s^2 and T=14N thanks
 
  • #10
Yes, it is!

ehild
 
  • #11
Hey Pat,

Could you describe what you've done to come up with those answers? I couldn't follow.

Cheers
 
  • #12
why do you want to follow, more cqu peoples?
 
Last edited:
  • #13
69camaro said:
Hey Pat,

Could you describe what you've done to come up with those answers? I couldn't follow.

Cheers

which part?
 

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