Inclined plane moment of inertia

[pat666]

Homework Statement

A block with mass m = 5.00 kg slides down a surface inclined 36.9 to the horizontal. The coefficient of kinetic friction is 0.25. A string attached to the block is wrapped around a flywheel has mass 25.0 kg and moment of inertia 0.500 kgm2 with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.200 m from that axis.
a) What is the acceleration of the block down the plane
b) What is the tension in the string

Homework Equations

The Attempt at a Solution

Ok I've been having a lot of trouble with things involving moments of inertia. I've found the friction that opposes the motion to be 9.81N. but how do i calculate the opposing force that the flywheel provides? any help is appreciated, as always..

 

[ehild]

Could you please show a picture?

ehild

 

[ehild]

Could you please show a picture?

ehild

 

[pat666]

How do you show a picture in a reply?? I've attached it as a word doc.

 

[Squeezebox]

Use the relationship $$\alpha$$=a/r and solve the torque equation for a.

 

[pat666]

you mean mg-T=ma??

 

[Squeezebox]

First sum up all of the forces for the block.

$$\Sigma$$F_x=sin$$\theta$$*F_g-F_f-T=ma

Then get the pulley

$$\Sigma\tau$$=I*$$\alpha$$

 

[pat666]

Ok ill do that and report back with my answer, thanks.

 

[pat666]

Hey is the answer a=1.123m/s^2 and T=14N thanks

 

[ehild]

Yes, it is!

ehild

 

[69camaro]

Hey Pat,

Could you describe what you've done to come up with those answers? I couldn't follow.

Cheers

 

[pat666]

why do you want to follow, more cqu peoples?

 

[pat666]

Hey Pat,

Could you describe what you've done to come up with those answers? I couldn't follow.

Cheers

which part?