Inclined Plane Problem-- Solving for Theta

Click For Summary
SUMMARY

The discussion centers on solving inclined plane problems in physics, specifically focusing on the forces acting on a block on an incline. The participant utilized the equation Fnet=ma and broke down gravitational force into its x and y components, leading to the expressions for normal force (N=mgcosx) and kinetic friction (F(kinetic friction)=mgcosxµk). The key realization was that when the block moves at constant speed, the acceleration (a) is zero, which simplifies the analysis. The participant plans to rework their calculations with this understanding.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of vector decomposition in physics
  • Familiarity with the concepts of kinetic friction and normal force
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the principles of inclined plane dynamics
  • Study the effects of friction on motion in physics
  • Learn how to apply Newton's second law in various scenarios
  • Explore problems involving constant velocity and acceleration
USEFUL FOR

Students studying physics, particularly those tackling mechanics and inclined plane problems, as well as educators looking for examples of problem-solving techniques in classical mechanics.

drdevil52
Messages
3
Reaction score
0

Homework Statement


These two problems are inclined plane problems which I cannot figure out. The problems are attached in the image below.

Homework Equations


Fnet=ma

The Attempt at a Solution


I first broke down the gravity force into its x and y components. After that, I did this:
mgsinx-F(kinetic friction)=ma

and found the expression for normal force: N=mgcosx

then found the expression for F(kinetic friction): mgcosxµk

I tried plugging in the expression for kinetic friction:

mgsinx-mgcosx(µk)=ma

I wasn't able to find an answer using this method so now I have no clue how to proceed.
 

Attachments

  • Screen Shot 2016-06-24 at 7.24.17 PM.png
    Screen Shot 2016-06-24 at 7.24.17 PM.png
    11.1 KB · Views: 997
Physics news on Phys.org
The important part of the question says (the print is too small for my eyes) the angle is adjusted so that the block has a constant speed of (can't read it) call it v.

Assume your equation is correct, what is the acceleration if the velocity is constant?
 
Oh I see, I completely overlooked that-- I mistook the velocity for acceleration. I'll rework this with a=0 and see if I can figure it out. Thanks!
 

Similar threads

Replies
2
Views
680
Replies
11
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K