Increase Entropy: Solve 0.15kg Ball Dropped from 24m Tower

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SUMMARY

The discussion focuses on calculating the increase in entropy of the universe when a 0.15 kg baseball is dropped from a height of 24 meters at an air temperature of 19 °C. The relevant equation for entropy change is ΔS = Q/T, where Q represents the heat transfer and T is the absolute temperature in Kelvin. Participants emphasize the importance of correctly identifying the object as a baseball, not a basketball, and clarify the gravitational constant as 6.7 x 10^-11 m^3/(kg x s^2) for further calculations.

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  • Understanding of thermodynamics, specifically entropy calculations
  • Familiarity with the equation ΔS = Q/T
  • Knowledge of gravitational constants and their applications
  • Basic principles of energy conservation in physics
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  • Study the principles of gravitational potential energy and its conversion
  • Learn about the calculation of entropy changes in various physical processes
  • Explore the implications of entropy in thermodynamic systems
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Students studying physics, particularly those focusing on thermodynamics and entropy, as well as educators seeking to clarify concepts related to energy and heat transfer in physical systems.

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Homework Statement



On a day when the air temperature is 19 °C, a 0.15 kg baseball is dropped from the top of a 24 m tower. After the ball hits the ground, bounces a few times, and comes to rest, by how much has the entropy of the universe increased?

Homework Equations



ΔS = Q/T

Also gravity is 6.7 x 10^ -11 m^3/(kg x s^2)

The Attempt at a Solution



I know that my answer should come out in units of J/K but I cannot remember how to work this problem and lost all of my notes. Please any help in getting me started would be greatly appreciated.
 
Last edited:
Physics news on Phys.org
How much energy does the basket ball have?
 
I like Serena said:
How much energy does the basket ball have?

There is no basketball, it's a baseball.
 

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