Proving Increasing Function: f'(x)=f(x) for all x

Click For Summary
To prove that the function f is increasing given that f'(x) = f(x) for all x, it is essential to recognize that if f'(x) > 0, then f is strictly increasing. Since f(x) is defined to be in the range (0, infinity), it follows that f(x) is always positive. Consequently, f'(x) = f(x) implies f'(x) > 0, confirming that f is indeed an increasing function for all x. This conclusion aligns with the properties of derivatives and the behavior of exponential functions. The discussion emphasizes the relationship between the positivity of the function and its derivative in establishing monotonicity.
kmeado07
Messages
40
Reaction score
0

Homework Statement



Let f : R(real numbers) (arrow) (0,infinity) have the property that f ' (x) = f (x) for all x. Show that f is an increasing functions for all x.

Homework Equations





The Attempt at a Solution



I know that if f ' (x) > 0 , where all of x belongs to a,b (not bounded) then f is strictly increasing on [a,b].

So i need to show that f(x) > 0 maybe?

Any help/guidelines would be much appreciated.
 
Physics news on Phys.org
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
8
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
892
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
4K