Indefinite Integral Calculus II

[Wm_Davies]

Homework Statement

\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx

Homework Equations

The Attempt at a Solution

\int \frac{ \tan x \sec^2 x }{ \tan^2 x + 6 \tan x + 8 } dx
Okay I let...

u=tanx
du=sec^2x


Then I got

\int \frac{ u }{ (u+4)(u+2) } du

Then I split this into partial fractions which is not working... for some reason. Can somebody please help me?

 

[LCKurtz]

\frac {2}{u+4} + \frac{-1}{u+2}