1. The problem statement, all variables and given/known data
2. The attempt at a solution
It's not even close. Since when does the integral of du/sqrt(u) have an ln in it? And shouldn't you be using du=(-5)dx to replace dx with du?
I forgot about the square root.
how about this?
I= ∫ dx/sqrt(2−5x)
= ∫ [1/sqrt(2−5x)]dx
(-1/5)du = dx
(-1/5) ∫ du/u^(1/2)
(-1/5) 1/ (2/3)u^(3/2)
du/sqrt(u) is u^(-1/2)du. You've still got the power rule wrong.
Do remember there is a way to check your work -- what relationship is a function supposed to have with its anti-derivatives?
Yeah, I already know that.
I don't trust my math, that's why I want to know if I'm doing this correctly.
ok nevermind I got it.....
Separate names with a comma.