Indeterminant forms homework help

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Homework Help Overview

The problem involves evaluating the limit as x approaches infinity for the expression sqrt(x^(2)+5x+11)-x, which is identified as an indeterminate form of type ∞-∞.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using L'Hospital's Rule and the 'conjugate' trick to simplify the expression. There are questions about the application of these methods and the challenges faced in manipulating the expression to resolve the indeterminate form.

Discussion Status

Some participants have offered guidance on using algebraic manipulation, specifically the conjugate, to address the limit without necessarily resorting to L'Hospital's Rule. The original poster expresses appreciation for the suggestions and indicates progress in understanding the problem.

Contextual Notes

The original poster notes that the professor has not covered similar problems in class, leading to some uncertainty in applying the concepts. There is also a mention of being ahead in the curriculum, which may limit opportunities for direct clarification from the instructor.

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Homework Statement



lim{x[itex]\rightarrow∞[/itex]} sqrt(x^(2)+5x+11)-x

Homework Equations



I know it is of type ∞-∞

The Attempt at a Solution



I have worked this problem around to death, and I know I'm supposed to give them a common denominator to get ∞/∞ and use L'Hospital's Rule, but I end up with ∞-∞ in the numerator or the denominator every time. Professor never went over problems this complex in class, and now we are too far ahead of this section to ask her to waste time going back to it.

I know the answer is 2.5 (graphing calculator), but my problem is figuring out how to work it.
 
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Try multiplying and dividing by sqrt(x^(2)+5x+11)+x. It's the 'conjugate' trick. It will turn out you don't really even need l'Hopital. You can do it all with algebra.
 
You are right you can use i'Hopital but after one differentiation, use: $$\sqrt{x^2 + 5x + 11} = \sqrt{x^2} \sqrt{1 + 5/x + 11/x^2}, $$ simplify and cancel terms and then take x → ##\infty##.
 
Thanks guys! I knew it had something to do with the conjugate, but for some reason I had trouble remembering just how it worked. I've worked it out now though, thanks for the help!
 

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