Index of refraction of the material

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Homework Help Overview

The problem involves a laser beam interacting with a wet paper placed on top of a glass plate, where the goal is to determine the index of refraction of the glass based on the radius of the light circle formed. The subject area pertains to optics and the behavior of light in different media.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the index of refraction using a relationship involving the radius of the light circle and the thickness of the glass plate. Some participants question the role of the wetness of the paper and its impact on the optical properties, while others explore the scattering mechanisms involved.

Discussion Status

The discussion is ongoing, with participants providing hints and exploring the implications of the wet paper on the problem. There is curiosity about the physical principles at play, particularly regarding scattering and light behavior in the context of the setup.

Contextual Notes

There are references to external sources for further understanding of the translucency of wet paper, and some uncertainty remains regarding the specific optical effects that the wetness introduces.

diredragon
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Homework Statement


A laser is fired into a wet paper placed ontop of a glass plate of thickness ##d## and an angle of ##0## degrees. When the light hits the paper and goes through the plate it forms a circle of light of radius ##R##. What is the index of refraction of the glass plate?

Homework Equations


3. The Attempt at a Solution [/B]
Apperently the answer is ##\frac{\sqrt{R^2+d^2}}{R}##. When the light hits the paper it bursts kind if...and forms a cone which base is the circle formed at the end but how was this proportion made. Its the ##\frac{1}{sinx}## where ##sinx## is the sine of te entry angle
 
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Hint: Paper is white because it scatters light evenly in the visible. I'm fairly sure the mechanism is Rayleigh scattering (paper is just wood pulp after all, so diffuse fibers, either that or its because of the absorbed water molecules being suspended in low density, I'm honestly not sure which but it doesn't affect the solution). The scattered light is reradiated in different directions. How much of this light is totally internally reflected?

Cool problem! Does anyone know why the paper has to be wet for it to work?
 
Twigg said:
Hint: Paper is white because it scatters light evenly in the visible. I'm fairly sure the mechanism is Rayleigh scattering (paper is just wood pulp after all, so diffuse fibers, either that or its because of the absorbed water molecules being suspended in low density, I'm honestly not sure which but it doesn't affect the solution). The scattered light is reradiated in different directions. How much of this light is totally internally reflected?

Cool problem! Does anyone know why the paper has to be wet for it to work?
We need to advertise this problem xD
 

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