Induced Current circuit problem

In summary, we are trying to find the current through section PQ of length a = 65.0cm in a circuit located in a changing magnetic field with magnitude B = (1.00 x 10^-3T/s)t. The resistance per length of the wire is 0.100 Ohm/meter. Two methods were attempted, one involving finding the emf generated in each loop and subtracting them to find the voltage across PQ, and the other using Kirchoff's circuit laws and modeling the loops as resistors. The correct answer is 283 x 10^-6A upward, with a discrepancy possibly due to rounding errors.
  • #1
Gear300
1,213
9
The circuit is shown below: Find the current through section PQ of length a = 65.0cm. The circuit is located in a magnetic field whose magnitude varies with time according to the expression B = (1.00 x 10^-3T/s)t. Assume the resistance per length of the wire is 0.100 Ohm/meter.

._________________P__________
.|xxxxxxxxxxxxxxxxxx|xxxxxxxxxxxx|
a|xxxxxxxxxxxxxxxxxx|xxxxxxxxxxxx|
.|xxxxxxxxxxxxxxxxxx|xxxxxxxxxxxx|
.|________________|__________|
---------2a--------Q-----a-----
The entire circuit is in a changing magnetic field that is going into the screen perpendicular to the plane of the circuit (nevermind the dashes between the 2a, Q, and a or the dots above and below the other a...they're just there for spacing).

I've tried several methods (actually, only 2 that I kept repeating, but they seemed right). The current along PQ should be found through finding the voltage between P and Q and using that (along with the resistance) to find the current. The actual answer is 283 x 10^-6A upward, but my answers don't match. Any help??
 
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  • #2
Show me what you have tried so far. Remember the forum rules: You must show your attempt at a solution to get help here.
 
  • #3
I thought that since there were 2 individual loops, I could take each one separately and find the emf the magnetic field would cause in each one. Since the magnetic field changes at a rate of 1.00x10^-3T/s and the area for each one is constant, the rate of change of magnetic flux, consequently the emf, through the larger loop would be .000845V through the larger loop and .000423V through the smaller loop. Since the 2 loops share a side PQ, I thought that the voltage along that side would be the subtraction of the 2 emfs. The result would be the voltage across PQ and since resistance is .1Ohm/m*.65m along PQ, I would use those two results to find the current. The answer I get from this is .0065A...which is not the answer.
 
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  • #4
I also get that answer for the current. I also agree with your method to find the solution. The fact that we are 3 factors of ten away from the correct answer makes me think some number is incorrect. Also the larger loop will have a larger induced emf and will induce a downward current along PQ due to the right hand rule, so the net current should be downward, not upward. Are you sure your numbers are correct?
 
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  • #5
pretty sure they are.
 
  • #6
I just did some searching on google after working on this problem for a few hours now myself... and this is what I have found. Basically you have to treat it like a kirchhoff rules problem.

physicsforums/archive/index.php/t-69984.html


(i am not allowed to post links apparently... but physicsforums.com goes where it says physicsforums)
Hope this helps
 
  • #7
heh...link doesn't work...thanks though.
 
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  • #8
pwelp is right - use Kirchoff's circuit laws.

The emf s you have calculated are correct but they are spread around each loop.

I found it helped to model each loop as 4 resistors of either 65mOhm (milliOhm) for 65cm sides or 130mOhm resistance for 130cm sides. The two loops share a 65mOhm resistor ie side PQ. Insert into each loop a battery of the emf you have calculated previously. Then solve using Kirchoff. This gave me an answer of 280 microA (rounding errors probably)
 
  • #9
Alright...to be sure, the emf generated in these loops is distributed across the loops, right?
 
  • #10
Yes there will be a potential difference across each resistor given by Ohm's law V=IR.
 
  • #11
alright then...thanks, I think I got it.
 

1. What is an induced current?

An induced current is an electric current that is created by a changing magnetic field. This can occur when a conductor, such as a wire, moves through a magnetic field or when a magnetic field changes in strength or direction near a conductor.

2. How does an induced current circuit work?

An induced current circuit works by using Faraday's law of induction, which states that a changing magnetic field will induce a voltage in a conductor. This voltage can then be used to create an electric current in the circuit.

3. What are some common problems encountered in induced current circuits?

Some common problems encountered in induced current circuits include electromagnetic interference, where the changing magnetic field can interfere with nearby electronic devices, and eddy currents, which can cause energy loss and heating in conductive materials.

4. How can induced current circuits be used in practical applications?

Induced current circuits have many practical applications, such as in generators, transformers, and motors. They are also used in wireless charging systems and in technologies such as electromagnetic brakes and induction cooktops.

5. How can induced current circuits be optimized for efficiency?

To optimize the efficiency of an induced current circuit, it is important to minimize electromagnetic interference and eddy currents. This can be achieved by using shielding materials, designing the circuit with the appropriate dimensions, and using materials with lower resistivity.

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