Induced current of a coil surrounding a solenoid

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SUMMARY

The discussion focuses on calculating the induced current in a coil surrounding a solenoid, specifically a coil with 170 turns and a resistance of 12 ohms, surrounding a solenoid with 230 turns per centimeter. The induced electromotive force (emf) is calculated using the formula induced emf = -(μ₀)(n)(A)(dI/dt), where the area A is crucial and should be based on the solenoid's radius. The correct induced current was found to be 0.053 A, but the direction of the current in the resistor was also a key point of contention, indicating the importance of correctly applying the right parameters in calculations.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for induced emf in a coil
  • Knowledge of solenoid characteristics, including turns per length
  • Basic proficiency in calculating area and flux in physics
NEXT STEPS
  • Review the derivation of the induced emf formula in electromagnetic induction
  • Study the application of Faraday's Law of Induction in various scenarios
  • Learn about the effects of resistance on induced current in circuits
  • Explore the relationship between solenoid design and induced emf calculations
USEFUL FOR

Physics students, educators, and professionals involved in electromagnetism and circuit analysis will benefit from this discussion, particularly those working on problems related to induced currents and solenoid applications.

jchoca
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Homework Statement


GIANCOLI.ch29.p67.jpg

A coil with 170 turns, a radius of 5.0 cm, and a resistance of 12 ohms surrounds a solenoid with 230 turns/cm and a radius of 4.7 cm; see the figure. The current in the solenoid changes at a constant rate from 0 to 1.8 A in 0.11 s.

Calculate the magnitude and direction of the induced current in the 170-turn coil.

Homework Equations


EQ1: induced emf (of a circular conducting loop surrounding a solenoid)
= -(mu_0)(n)(A)(dI/dt)
where n is the turns per length in the solenoid with changing current dI/dt and loop of area A.
EQ2: induced emf = -(dflux/dt)
EQ3: flux = BA
EQ4: B_solenoid = (mu_0)(n)(I)
EQ5: I_induced = (induced emf)/R

The Attempt at a Solution



I tried to take equation 1 and compute the emf for a single loop, then I multiplied that times 170. I then divided that by 12 to get the current. However, MP says it's wrong. My result was 0.053 A using n = 23,000 turns/m, A = pi * 0.05^2, and dI/dt = 1.8/0.11.

Note: Problem is #67 from Ch 29 of Physics for Scientists and Engineers with Modern Physics By Douglas C. Giancoli, 4th ed.
 
Last edited:
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I got the same number for the current as you. What direction did you give for the current in 12 Ω resistor? Maybe that's what you got wrong.
 
jchoca said:
EQ1: induced emf (of a circular conducting loop surrounding a solenoid)
= -(mu_0)(n)(A)(dI/dt)
where n is the turns per length in the solenoid with changing current dI/dt and loop of area A.

The B field is confined to the solenoid. Instead of the area of the loop, you should use the area of the solenoid.

jchoca said:
My result was 0.053 A using ... A = pi * 0.05^2 ...
This is not the correct radius for calculating the area of the solenoid.
 
TSny said:
This is not the correct radius for calculating the area of the solenoid.
Oops, I missed that even though I looked to make sure that the correct solenoid radius was used. :headbang:
 
kuruman said:
Oops, I missed that even though I looked to make sure that the correct solenoid radius was used.
No problem. We're going to miss things.
 

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