Induced emf generation problem

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Homework Help Overview

The problem involves a metal rod moving along parallel rails in a magnetic field, specifically focusing on the induced electromotive force (emf) generated due to this motion. The magnetic field strength and the dimensions of the setup are provided, along with the velocity of the rod.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of emf and the significance of the negative sign in Faraday's law. Questions arise regarding the interpretation of the problem's request for magnitude versus direction, and the meaning of the direction of emf.

Discussion Status

Some participants have provided insights into the interpretation of the problem, noting that the absence of a request for direction may imply that only the magnitude is needed. Others are exploring the implications of the negative sign in the context of Lenz's law and the direction of induced current.

Contextual Notes

Participants are considering the implications of the problem's wording and the assumptions that can be drawn from it, particularly regarding the expected answers and the definitions of direction in the context of induced emf.

mbrmbrg
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Homework Statement



In Figure 30-52 (see attached), a metal rod is forced to move with constant velocity v along two parallel metal rails, connected with a strip of metal at one end. A magnetic field B = 0.370 T points out of the page.


(a) If the rails are separated by 26.0 cm and the speed of the rod is 65.0 cm/s, what emf is generated?


Homework Equations



\phi_B=\oint \vec{B}\cdot d\vec{A}

\varepsilon=-\frac{d\phi_B}{dt}

v=\dot{x}

The Attempt at a Solution



I got the correct numerical answer, just my sign is off for part a.

\varepsilon=-\frac{d\phi_B}{dt}

\varepsilon=-\frac{\vec{B}\cdot d\vec{A}}{dt}

\varepsilon=-\frac{BLdx}{dt}

\varepsilon=-BLv

\varepsilon=-(0.370T)(0.26m)(0.65m/s)

\varepsilon=-0.00625V

Book says there is no negative in the final answer.:confused:
 

Attachments

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The minus sign in Faraday's law tells you that the direction of induced EMF opposes the change in flux. But all they want is the magnitude, which is positive. (If they wanted the direction, you'd have to specify clockwise or counterclockwise per Lenz's law.)
 
What in the problem should tip me off that they want only magnitude?

Also, what is the meaning of direction of emf? Is it the direction of the induced field lines?
 
mbrmbrg said:
What in the problem should tip me off that they want only magnitude?
That they didn't ask for direction? :smile: (Sorry!) But realize that a negative answer doesn't mean much.

Also, what is the meaning of direction of emf? Is it the direction of the induced field lines?
You can specify the direction in terms of the direction of the induced current the EMF would drive. What would the direction of the EMF/induced current be in this problem?

Read this (especially the section on Lenz's law): http://hyperphysics.phy-astr.gsu.edu/hbase/electric/farlaw.html"
 
Last edited by a moderator:
Doc Al said:
That they didn't ask for direction? :smile: (Sorry!) But realize that a negative answer doesn't mean much.
:redface: Hmmm... I thought that unless otherwise specified, a direction was expected.

You can specify the direction in terms of the direction of the induced current the EMF would drive. What would the direction of the EMF/induced current be in this problem?

Oh. OK. I figured out that the current should be clockwise (which the problem states to be the negative direction), so the direction of the emf is clockwise/negative, as well.
 

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