Inductance of DC Electromagnet Coil. Help

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Discussion Overview

The discussion revolves around calculating the inductance of a DC electromagnet coil, with participants exploring the relationship between resistance, impedance, and inductance. The context includes technical reasoning and mathematical relationships relevant to electrical circuits.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant describes their setup for a DC electromagnet coil, providing resistance and impedance values but seeking help to find the inductance.
  • Another participant questions whether the voltage is alternating or direct current and asks for the frequency if it is AC.
  • A different participant proposes a mathematical relationship using resistance and inductance to calculate inductance, suggesting a formula involving impedance.
  • Some participants emphasize the necessity of knowing the frequency to accurately calculate inductance, referencing the relationship between inductive reactance and frequency.

Areas of Agreement / Disagreement

Participants generally agree on the importance of frequency in calculating inductance, but there is no consensus on the correct approach or the specific values to use in the calculations.

Contextual Notes

The discussion highlights the dependence on frequency for accurate calculations and the potential limitations in the provided data, such as the lack of clarity on whether the voltage is AC or DC.

wingsofdesire
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I am trying to make a DC electro magnet coil. The Coil is wound up to the core. And works fine. But I'm not being able to find out the inductance of the coil. The Resistance of Coil R20= 490 ohms. Impedence is 523 Ohms. 110v give .21 amps. Please Help.
 
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Is the 110v alternating or direct current? If alternating current, what is its frequency?
 
modmix said:
what about this:
Given we have just R and L (no C).
They from a triangle: Z^2 = R^2 + L^2.
=> L = sqrt(Z^2 - R^2) = 182 Ohm.

hth
Ulli

That is not correct, you need to know the frequency as has been hinted at. XL = ωL
 
You say 110volts so I would guess that f = 60Hz (or maybe 50Hz)
The impedance = 110/0.21 = 523Ω. ω Is 2∏60 = 377
So if you do 5232 = 4902 + (ωL)2...see what you get for L.
 
technician said:
That is not correct, you need to know the frequency as has been hinted at. XL = ωL
sure. that's why i deleted my posting - not fast enough...
L measures in H ,-)
 

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