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Induction motor locked rotor test

  1. Apr 23, 2016 #1
    induction motor.PNG

    For the locked rotor test I have these values,
    P1 = 620W
    Stator line voltage = 32V
    Stator line current = 8.4A

    To calculate active power/phase,

    Po = (P1+P2)/3

    But I don't have P2, Is P1 maybe equal to P2 ?
     
  2. jcsd
  3. Apr 23, 2016 #2

    jim hardy

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    Last edited: Apr 23, 2016
  4. Apr 23, 2016 #3
    Yes, it is

    To calculate P2, I got this formula from the second link
    Wa = VL*IL*cos(30+∅)
    Wb = VL*IL*cos(30-∅)

    If this is the formula and I know Wa = 620W then what is VL and IL

    Is that how I calculate P2 ?
     
  5. Apr 23, 2016 #4

    jim hardy

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    Good - you went to second link which is same connection as you showed .

    upload_2016-4-23_8-56-40.png

    What you measured on the voltmeter and ammeter.

    upload_2016-4-23_9-5-3.png
    Since you only measured one phase you'll have to assume it's balanced . Would be advisable to check that too when you re-test.

    Observe how thorough that author was in defining his quantities
    he clarified that VL means line to line not line to neutral

    That is an important habit to form early ; without it three phase will be confusing.
     
  6. Apr 23, 2016 #5
    If I use VL = 32V and IL = 8.4A and Wa = 620W

    620 = 32*8.4*cos(30+∅)
    cos(30+∅) = 2.31

    But that cant be true

    By the way, what I am actually trying to calculate is r1+r2' and X, given by this equivalent circuit

    upload_2016-4-23_18-35-21.png

    upload_2016-4-23_18-36-33.png
     
  7. Apr 23, 2016 #6

    jim hardy

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    Good one ! I missed that, admittedly i didn't try out your numbers....

    So we have an impossible result , a wattmeter reporting power factor over unity (the free energy crowd will love that !)
    Therefore we must question our observations and root out what mistake(s) led us into that impossible conclusion ?

    P1 reported 620 watts with 32 volts and 8.4 amps - something looks fishy there.
    I note you show a CT but no PT(voltage stepdown transformer)
    Look at the back of PI . Does it assume any PT ratio and CT ratios?
    or Is full scale on P1 equal to 5A X 400V = 2000 Watts ?

    If the latter, P1 will under-report power by the CT ratio
    With CT set on 10::5 , 1240 watts would report as 620
    with CT set on 20::5 , it'd take 2480 to report as 620



    Sorry to be so uncertain - please realize i wasn't there and haven't seen your instruments. I'm accustomed to analog antiques in oak boxes..

    In school labs it's not unusual for CT's to get blown........ they're easily hurt by passing primary current with secondary open circuited.. That pierces insulation on secondary winding and they thereafter report way low. i hope that's not your trouble.

    First i'd see if you get more reasonable results from multiplying wattmeter readings by whatever was your CT ratio , 2 or 4.

    old jim
     
  8. Apr 24, 2016 #7
    Yeah, I think the wattmeter reading might be wrong. Will have to check it up in the lab again.
    Thanks
     
  9. Apr 24, 2016 #8

    jim hardy

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    i didnt do anything, but thanks for the feedback.

    8.4 amps is the current measured where ? If on your 5 amp ammeter, the CT is being overworked and likely is introducing undue phase shift.... and so is the wattmeter's current coil..

    Labs teach us more through serendipity than through the intended lesson.
    Like Thoreau's Bean Field.

    old jim
     
  10. Apr 25, 2016 #9
    The actual current measured on the ammeter was 4.2A, but the CT ratio is 2:1 so 4.2A*2 = 8.4A
     
  11. Apr 25, 2016 #10

    jim hardy

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    That's Good news... Thanks

    I know it seemed a dumb thing to ask
    but i've fixed a lot of troubles by checking the dumb things first.
    When working alone , one doesn't have to confess that he looked at them.
    Please do not think i am talking down to you - this is just how i work. It's okay to be slow but sure footed .

    So mr Wattmeter reported 620 watts with 4.2 amps and 32 volts, when he couldn't have received more than 134.4.
    High by at least 4.6 , nearest integer to that is 5.

    I'm guessing that Mr Wattmeter is expecting a CT with higher ratio.
    But that's just a guess.
    Check his nameplate, meter face, instruction leaflet ......
     
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