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huh

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**almost there-inelastic collision at an angle**

Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 2v, while the second was traveling at speed v at an angle phi south of east. After the collision, the two-car system travels at speed v(final) at an angle theta east of north.

I want to find v(final) in terms of v and phi.

Only momentum is conserved, so would I just use m1(2v1)+m2v2cos(phi)=(m1+v1)v(final)sin(theta)

or could it be (m1+m2)2vcos(phi) divided by (m1+m2)

I'm not sure how to set up the equation...I've been confusing myself...

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