Infinite series of complex numbers.

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The discussion centers on the infinite series of complex numbers represented by C and S, where C = 1 + (1/3)cosx + (1/9)cos2x + ... and S = (1/3)sinx + (1/9)sin2x + ... The user successfully identifies that C + jS can be expressed as a geometric series with a common ratio of (1/3)Z, leading to the sum to infinity formula 3/(3-Z). The next step involves breaking down the expression into real and imaginary components, specifically using z = cosx + jsinx.

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I have the two series:
C = 1 + (1/3)cosx + (1/9)cos2x + (1/27)cos3x ... (1/3^n)cosnx
S = (1/3) sinx + (1/9)sin2x ... (1/3^n)sinnx

I have to express, in terms of x, the sum to infinity of these two series.

Here's what I've done so far:
Let z represent cosx + jsinx
C + jS = z^0 + (1/3)Z^1 ... (1/3)^n(Z^n)
This is a GP with first term 1, common ratio (1/3)Z.
Sum to infinity of C + jS = a/(1-r) = 3/(3-Z)

I can't seem to find where to go from there. Can anyone help?

Thankyou.
 
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Write z=x+iy and break your answer, 3/(3-z) into real and imaginary parts.

Carl
 

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