The discussion focuses on calculating the nonlinearity error of a non-linear pressure sensor with an input range of 0 to 10 bar and an output range of 0 to 5V. The output voltage at 4 bar is measured at 2.2V, while the expected output based on a linear model (y=1/2x) is 2V. The nonlinearity error is determined by the difference of 0.2V, which needs to be expressed as a percentage of the full scale (10 bar). The calculation of this percentage is the key conclusion of the discussion.
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bos1234 said:Homework Statement
A non-linear oressure sensor has an input range of 0 to 10 bar and an output range of 0 to 5V. The output voltage at 4 bar is 2.2V. The nonlinearity as a percentage of psan is?
Homework Equations
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The Attempt at a Solution
Drew a straight line using the data given with equation y=1/2x. (0-10 on x-axis;0-5v on y-axis). Therefore at x=4, y=2. 2.2-2=0.2?