Can someone help me with this integral?
Solving this will take some adroit trig substitutions. Half angle formulae, particularly that for tan(x/2), will come in handy here.
Good so far.Than I get
= ln (tan(x/2) +1)
Whoa! What's this last step?= ln ((sin(x/2) / cos(x/2)) +1)
= ln (sin(x/2) +1) - ln(cos(x/2)+1)
Good so far.
Whoa! What's this last step?
For that matter, why do you need to go beyond ln(tan(x/2)+1) ? That is a perfectly good answer in and of itself.