Integrating 1/2x: Comparing Methods and Solutions

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SUMMARY

The discussion focuses on the integration of the function ∫(1/2x)dx, where two methods yield valid results. The first method factors out (1/2), leading to the solution (1/2)ln|x| + C. The second method employs a substitution with u=2x, resulting in (1/2)ln|2x| + C. Both approaches are mathematically correct, as they differ by a constant, specifically ln(2), which can be absorbed into the integration constant C.

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Homework Statement



∫(1/2x)dx

The Attempt at a Solution



I factor out (1/2) and i get ∫(1/2x)dx=(1/2)ln|x|+C
∫(1/2x)dx
(1/2)∫(1/x)dx
(1/2)ln|x|+C

But can't i say that u=2x and dx=du/2 and get ∫(1/2x)dx= (1/2)ln|2x| + C
∫(1/2x)dx
u=2x
∫(1/u)(du/2)
∫(1/2u)du
(1/2)∫(1/u)dx
(1/2)ln|u| + C
(1/2)ln|2x| + C

if i can do this, i get two different answers...

can i use the last method?
 
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ln 2x = ln x + ln 2. One of your C constants is equal to the other plus ln 2.

Both your answers are right...
 
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