(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the area between y= 1/(x^{2}+1) and the x-axis, from x=0 to x=1

3. The attempt at a solution

so when x=0, y=1

and when x=1, y=1/2

next i plot the points, so the intersection of the given equation is (0,1) and (1,1/2)

Yh= Y-higher= 1/(x^{2}+1)

Yl= Y-lower= 0

the strip is vertical, so the length (L) = (Yh-Yl) and the width (W) is dx

dA=LW

dA=(Yh-Yl)dx

dA=(1/(x^{2}+1))dx

A=∫from 0-1 dx/(x^{2}+1)

A=Arctan x from 0-1

A=Arctan 1 -Arctan 0

A=pi/4 sq.units

was my solution correct?

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# Integral calculus: plane areas in rectangular coordinates

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