Integral Domain: Solving a^2=1 with at Most 2 Solutions

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SUMMARY

In an integral domain R with identity element 1, the equation a^2=1 has at most two solutions. This conclusion arises from the property of integral domains that states if ab=0, then either a=0 or b=0. The equation a^2=1 can be rewritten as a^2-1=0, which factors to (a-1)(a+1)=0, indicating that the possible solutions are a=1 and a=-1. Therefore, the only elements satisfying the equation are 1 and -1, confirming that there are at most two solutions.

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Homework Statement



Let R be an integral domain with identity element 1. Show that there at most two elements "a" in R such that a^2=1


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The Attempt at a Solution



Being an integral domain implies that if ab=0, then a=0 or b=0. a^2=1 implies a=1. Then (a)(a) = (1)(1). This seems like a simple problem but I'm not sure how to properly state that there are "at most 2 elements."
 
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Saying that a2=1, is thesame as saying that a2-1=0. Maybe you can factorize the left hand side...
 
Thank you. Got it
 

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