Integral Homework Help: Solving ∫ dy/√(y²+C) Using ln and sinh^-1 Methods

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Homework Help Overview

The discussion revolves around solving the integral \(\int \frac{dy}{\sqrt{y^2 + C}}\), with participants exploring different methods of integration, including logarithmic and inverse hyperbolic functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss potential solutions, questioning whether the integral can be expressed in terms of logarithmic functions or inverse hyperbolic functions. There is mention of substituting \(y\) with \(C \sinh(u)\) to explore the integral further.

Discussion Status

Multiple interpretations of the integral's solution are being explored, with some participants suggesting that both logarithmic and inverse hyperbolic forms may be valid. There is acknowledgment of a connection between the two expressions, indicating a productive exchange of ideas.

Contextual Notes

Some participants reference a related differential equation, which may influence their approach to the integral, though the specifics of this connection are not fully detailed.

Ed Aboud
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Homework Statement



I'm trying to solve [tex]\int \frac{dy}{\sqrt{y^2 + C}}[/tex]

Homework Equations





The Attempt at a Solution



Is it [tex]ln |y + \sqrt{y^2 + C^2} |[/tex]

Or is it [tex]sinh^-^1[/tex] something.

Thanks.
 
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It might be both, your first expression looks rather like sinh^(-1) to me as well. Why don't you try doing it? Put y=C*sinh(u) (assuming you mean y^2+C^2 in the integrand).
 


It turns out that its [tex]sinh^-^1 (\frac{y}{c})[/tex]

Because my original differential equation was [tex]\frac{d^2y}{dt^2} - y = 0[/tex]

Thanks!
 


arcsinh(y/C)=ln(y/C+sqrt(y^2/C^2+1)). That's the same as ln(y+sqrt(y^2+C^2)) up to a constant. They are both right.
 

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