Integral of a continuously differentiable function on [a,b].

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rsa58
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suppose f is real, continuously differentiable function on [a,b], f(a)=f(b)=0 and

integral f^2dx=1

show [integral(xf(x)f'(x)dx)= -1/2 over [a,b]
 
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How can you write the term [tex]f(x)\,f'(x)[/tex]?
 
rsa58 said:
suppose f is real, continuously differentiable function on [a,b], f(a)=f(b)=0 and

integral f^2dx=1

show [integral(xf(x)f'(x)dx)= -1/2 over [a,b]
Integrate by parts:

You will get 1/2(bf2(b)-af2(a)-integral(a,b)f2(x))