: Integral of (n+1)th derivative

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Homework Help Overview

The problem involves the integral of the (n+1)th derivative of a function, with a focus on demonstrating a specific equation related to integrals and derivatives over a defined interval. The subject area pertains to calculus, particularly integration and differentiation techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using induction as a method to prove the equation, with suggestions to start by computing the integral for specific values of n. There is also mention of applying integration by parts to facilitate the process.

Discussion Status

The discussion is ongoing, with some participants offering guidance on how to approach the problem through induction and integration by parts. There appears to be a collaborative effort to clarify the steps needed to tackle the integral.

Contextual Notes

Participants note the urgency of the request for help and the original poster expresses frustration over a lack of progress after significant effort. The problem may involve assumptions about the integrability of the function and the conditions under which the equation holds.

kfdleb
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URGENT: Integral of (n+1)th derivative

Homework Statement



let f(n+1) be integrable on [a;b]; show that

f(b)=[tex]\sum[/tex] [tex]\frac{f<sup>(r)</sup>(a)}{r!}[/tex](b-a)r +[tex]\frac{1}{n!}[/tex] [tex]\int^{a}_{b}[/tex]f(n+1)(t)(b-t)ndthint:integrate by parts and use inductionPLEASE any idea about how to solve it would be really appreciated... I've been trying for more than an hour but no idea
 
Last edited:
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Well use the hint. Induct on n. For n = 1, show the equation holds by computing the integral that you get on the RHS after setting n = 1. This is fairly straightforward.
 


Start by actually doing the integration by parts. Treat the integral as u*dv where u=f^(n+1)(t) and dv=(b-t)^n*dt. Once you've got that straight then start worrying about the induction.
 


10x a lot
 

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