(adsbygoogle = window.adsbygoogle || []).push({}); Integral of unknown difficulty!!

1. The problem statement, all variables and given/known data

integral of: 1/[4+5sin(2x)] dx

3. The attempt at a solution

U substitution on 2x gives u=2x

then du becomes 2dx so... du=2 dx

after that, i get

1/2 * int of: 1/[4+5sin(u)] du

from here, using v=5sin(u)

then: dv=5cos(u) du

this is where i get stuck. Did i start it off right or did I mess it up here? I dont need the answer to it, just a push in the right direction from the start ><

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# Homework Help: Integral of unknown difficulty

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