Integral of -: (v^2+2v-1)/(v^3+v^2+v+1)

[amaresh92]

how to find the integral of -: (v^2+2v-1)/(v^3+v^2+v+1)

advanced thanks.

 

[arildno]

Partial fractions decomposition.

Note that the denominator is divisible by (v+1):
$$(v^{3}+v^{2}+v+1)/(v+1)=v^{2}+1$$

 

[losiu99]

Notice that $$v^3+v^2+v+1=(v+1)(v^2+1)$$. Use the method of partial fractions, once it's done it's very easy.

 

[arildno]

Notice that $$v^3+v^2+v+1=(v+1)(v^2+1)$$. Use the method of partial fractions, once it's done it's very easy.

HA! I beat you to it!
We oldies are still the best!

 

[losiu99]

Yeah, soo true Maybe next time...