Integral problem on electric potential

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SUMMARY

The discussion focuses on calculating the electric potential V(r) for a long metal cylinder with radius a, positioned within a hollow metal tube of radius b, where the inner cylinder carries a positive charge per unit length λ and the outer cylinder carries an equal negative charge. The key equation used is Va - Vb = ∫E·dr, derived from Gauss's law. A critical point raised is the confusion regarding the limits of integration from a to b, despite the evaluation being for r < a, highlighting the necessity of understanding potential calculations in electrostatics.

PREREQUISITES
  • Understanding of Gauss's law in electrostatics
  • Familiarity with electric potential and its calculation
  • Knowledge of integration techniques in physics
  • Concept of electric field due to cylindrical charge distributions
NEXT STEPS
  • Study the application of Gauss's law in cylindrical symmetry
  • Learn about electric potential calculations in electrostatics
  • Explore the concept of electric field and potential at different radial distances
  • Investigate the implications of charge distribution on electric fields
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as educators and professionals involved in teaching or applying concepts of electric potential and fields in cylindrical geometries.

venom_h
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Homework Statement



A long metal cylinder with radius a is held on the axis of a long, hollow, metal tube with radius b. The inner cylinder has positive charge per unit length [tex]\lambda[/tex], and the outer cylinder has an equal negative charge per unit length. Calculate the potential V(r) for r<a


Homework Equations



Va-Vb = [tex]\int[/tex]E.dr, where E can be found by Gauss's law

The Attempt at a Solution



My only problem is why the limit for the integral is from a to b even though r < a ??
How does any point r < a experience a potential outside??
[
 
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If you take the potential at infinity to be 0... then the potential at any radius r is,

[tex]V(r) = -\int_{\infty}^r \vec{E}\cdot\vec{dr}[/tex]

assuming b is the outer radius, and a is the inner radius

[tex]V(a) = -\int_{\infty}^a \vec{E}\cdot\vec{dr} = -\int_{\infty}^b \vec{E}\cdot\vec{dr} - \int_{b}^a \vec{E}\cdot\vec{dr}[/tex]
 

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