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## Homework Statement

integral of 1/(x^2 + z^2)^(3/2) dx,

where z is a constant

## Homework Equations

## The Attempt at a Solution

I set u = arctan(x/z) so du = z/(x^2 + z^2) dx but now I'm honestly stuck.

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- Thread starter walksintoabar
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- #1

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integral of 1/(x^2 + z^2)^(3/2) dx,

where z is a constant

I set u = arctan(x/z) so du = z/(x^2 + z^2) dx but now I'm honestly stuck.

- #2

Dick

Science Advisor

Homework Helper

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- #3

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[tex] x=z\sinh t [/tex]

is also a valid substitution.

is also a valid substitution.

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