Integral - u substitution with arctan

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SUMMARY

The integral of 1/(x^2 + z^2)^(3/2) dx can be effectively solved using the substitution x = z*tan(u), which leads to dx = z*sec(u)^2*du. This method simplifies the integral into a more manageable form, allowing for the application of trigonometric identities. An alternative substitution, x = z*sinh(t), is also valid and may yield similar results. Both approaches leverage the properties of trigonometric and hyperbolic functions to facilitate the integration process.

PREREQUISITES
  • Understanding of integral calculus and substitution methods
  • Familiarity with trigonometric functions and identities
  • Knowledge of hyperbolic functions and their properties
  • Ability to manipulate differential equations
NEXT STEPS
  • Study the application of trigonometric substitution in integrals
  • Learn about hyperbolic function identities and their uses in calculus
  • Explore advanced integration techniques, including integration by parts
  • Practice solving integrals involving arctan and other inverse trigonometric functions
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for effective methods to teach integral calculus concepts.

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Homework Statement


integral of 1/(x^2 + z^2)^(3/2) dx,
where z is a constant

Homework Equations



The Attempt at a Solution


I set u = arctan(x/z) so du = z/(x^2 + z^2) dx but now I'm honestly stuck.
 
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You've got the correct substitution but you are thinking of this in a kind of convoluted way. Just put x=z*tan(u), so dx=z*sec(u)^2*du. Factor out a power of z and do the trig integral in u.
 
x=z\sinh t

is also a valid substitution.
 

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