Integral with transformations and bounded by x + y + z = 1

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Homework Help Overview

The discussion revolves around evaluating a triple integral of the form dxdydz/(y+z) under the constraints x >= 0, y >= 0, z >= 0, and bounded by the equation x + y + z = 1. The original poster mentions specific transformations to be used: x = u(1-v), y = uv(1-w), z = uvw.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to express the integral in terms of the new variables and questions the appropriate bounds for integration. Some participants inquire about the source of the transformations and suggest considering the bounds in terms of the original variables if the new ones are unclear.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the transformations and the necessity of including the full problem statement. There is a suggestion that using the original variables might simplify the integration process.

Contextual Notes

There is a noted concern regarding the clarity of the problem statement and the prescribed transformations, which may affect the ability to determine the integration bounds accurately.

Cyn
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Homework Statement


I have a question. I need to know the integral dxdydz/(y+z) where x>=0, y>=0, z>=0.

Homework Equations


It is bounded by x + y + z = 1. The transformations I need to use are x=u(1-v), y=uv(1-w), z=uvw.

The Attempt at a Solution


y+z = uv. J = uv(v-v^2+uv)
So I get the integral (v-v^2+uv)dudvdw. But I don't know which bounds I need to use. Is this correct and how can I know the bounds?
 
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Cyn said:
The transformations I need to use are x=u(1-v), y=uv(1-w), z=uvw
Does the exercise text prescribe this ? Your problem statement doesn't -- could you please post the full problem statement ?

For a start: If you can't write the bounds in terms of u, v and w, can you give them in terms of x, y and z ?
 
Cyn said:

Homework Statement


I have a question. I need to know the integral dxdydz/(y+z) where x>=0, y>=0, z>=0.

Homework Equations


It is bounded by x + y + z = 1. The transformations I need to use are x=u(1-v), y=uv(1-w), z=uvw.

The Attempt at a Solution


y+z = uv. J = uv(v-v^2+uv)
So I get the integral (v-v^2+uv)dudvdw. But I don't know which bounds I need to use. Is this correct and how can I know the bounds?

If somebody is forcing you to use the transformation, then I guess you are stuck with it. However, just doing repeated integrations in terms of x, y, z is much more straighforward.
 
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It's a good idea to include the whole problem statement in the main body of you post. If a part of the problem statement is contained in the thread title, please repeat that part in the body of the Original Post.

Integral with transformations and bounded by x + y + z = 1

Cyn said:

Homework Statement


I have a question. I need to know the integral dxdydz/(y+z) where x>=0, y>=0, z>=0.

Homework Equations


It is bounded by x + y + z = 1. The transformations I need to use are x=u(1-v), y=uv(1-w), z=uvw.

The Attempt at a Solution


y+z = uv. J = uv(v-v^2+uv)
So I get the integral (v-v^2+uv)dudvdw. But I don't know which bounds I need to use. Is this correct and how can I know the bounds?
 

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