Chipset3600
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Hello MHB, how can i solve this without use integration technniques...
\int tan(t)sec^3(t)dt
\int tan(t)sec^3(t)dt
The discussion revolves around the integral \(\int \tan(t) \sec^3(t) dt\) and explores methods to solve it without employing traditional integration techniques such as substitution or integration by parts. Participants express varying opinions on the feasibility of this approach.
Participants express disagreement regarding the possibility of solving the integral without integration techniques. Some believe it is not feasible, while others attempt to propose solutions that still reference integration concepts.
The discussion highlights limitations in the proposed methods, particularly the reliance on integration concepts despite attempts to avoid them. There is also an acknowledgment of the integral's non-elementary nature.
Chipset3600 said:Hello MHB, how can i solve this without use integration technniques...
\int tan(t)sec^3(t)dt
SuperSonic4 said:How do you mean "without using integration techniques"? Surely you need integration techniques to solve an integral? Also what have you tried?
Hint: Let $u = \sec(t) = \frac{1}{\cos(t)}$
Well, maybe you can see all this?If we have: .f(x) \:=\:\tfrac{1}{3}\sec^3\!\theta + CHow can i solve this without use integration technniques?
. . \int \tan\theta \sec^3\!\theta\,d\theta
soroban said:Hello, Chipset3600!
Well, maybe you can see all this?If we have: .f(x) \:=\:\tfrac{1}{3}\sec^3\!\theta + C
Then: .f'(x) \:=\:\tfrac{1}{3}\cdot 3\sec^2\!\theta\cdot\sec\theta\tan\theta + 0 \;=\;\tan\theta\sec^3\!\theta