Integrals of (-3csc(theta))/(1+cos(theta))

  • Thread starter Thread starter Jessicamgray
  • Start date Start date
  • Tags Tags
    Integrals
Click For Summary
SUMMARY

The integral of (-3csc(theta))/(1+cos(theta)) can be solved using substitution techniques. The recommended approach involves multiplying the integrand by sin(theta)/sin(theta) to introduce a sine term in the numerator, facilitating the use of u-substitution. Specifically, setting u = cos(theta) simplifies the integration process, allowing for the application of trigonometric identities to express the remaining functions in terms of u. This method effectively addresses the challenges posed by the original integrand.

PREREQUISITES
  • Understanding of trigonometric functions, specifically csc(theta) and cos(theta)
  • Familiarity with u-substitution in integral calculus
  • Knowledge of trigonometric identities
  • Basic skills in manipulating algebraic expressions
NEXT STEPS
  • Practice integration techniques involving trigonometric functions
  • Learn about advanced u-substitution methods in calculus
  • Study trigonometric identities and their applications in integration
  • Explore the use of integration by parts for complex integrals
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators seeking to enhance their teaching methods for trigonometric integrals.

Jessicamgray
Messages
1
Reaction score
0

Homework Statement


integrate (-3csc(theta))/(1+cos(theta))

Homework Equations


i'm not sure

The Attempt at a Solution


i tried using u sub. but i got nowhere.

U=1+costheta
Du=-sintheta
 
Physics news on Phys.org
Jessicamgray said:

Homework Statement


integrate (-3csc(theta))/(1+cos(theta))

Homework Equations


i'm not sure

The Attempt at a Solution


i tried using u sub. but i got nowhere.

U=1+costheta
Du=-sintheta

The reason why your ##u##-sub doesn't get you anywhere (yet) is because (1) there isn't a ##\sin\theta## in the numerator and (2) we'd still need to deal with the ##\csc\theta##. I recommend that you

(1) Put a ##\sin\theta## in the numerator so that your ##u##-sub at least has a chance of working. Of course you can't just put one there, but you can multiply the integrand by ##\frac{\sin\theta}{\sin\theta}## so that there is one there.

(2) Write the ##\csc\theta## in terms of ##\sin\theta## and see if you can make something happen with what you end up with.
 
I'd try just u=cos(theta). Then since du=sin(theta)dtheta multiply numerator and denominator by sin(theta). That gives you your du. Now see if you can use trig identities to express the other functions of theta as u.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
Replies
28
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K